you are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. interpret the results and compare the widths of the confidence intervals. if convenient, use technology to construct the confidence intervals.
a random sample of 55 home theater systems has a mean price of $113.00. Assume the population standard deviation is $16.50
1)for 90% CI:
sample mean 'x̄= | 113.000 |
sample size n= | 55.00 |
std deviation σ= | 16.500 |
std error ='σx=σ/√n= | 2.2249 |
for 90 % CI value of z= | 1.645 | |
margin of error E=z*std error = | 3.660 | |
lower bound=sample mean-E= | 109.34 | |
Upper bound=sample mean+E= | 116.66 | |
from above 90% confidence interval for population mean =(109.34,116.66) |
above interval gives 90% confidence to contain true value of population mean |
for 95% CI:
for 95 % CI value of z= | 1.960 | |
margin of error E=z*std error = | 4.361 | |
lower bound=sample mean-E= | 108.64 | |
Upper bound=sample mean+E= | 117.36 | |
95% confidence interval for population mean =(108.64,117.36) | ||
above interval gives 95% confidence to contain true value of population mean |
95% confidence interval has larger width.
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