Question

A doctor wants to estimate the HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the HDL cholesterol within 3 points with 99 % confidence assuming sigma equals 13.5 question mark Suppose the doctor would be content with 95 % confidence. How does the decrease in confidence affect the sample size required? A 99% confidence level requires nothing subjects. (Round up to the nearest whole number as needed.) A 95 % confidence level requires nothing subjects. (Round up to the nearest whole number as needed.) How does the decrease in confidence affect the sample size required? A. The lower the confidence level the smaller the sample size. B. The lower the confidence level the larger the sample size. C. The sample size is the same for all levels of confidence

Answer #1

The following information is provided,

Significance Level, α = 0.05, Margin or Error, E = 3, σ = 13.5

The critical value for significance level, α = 0.05 is 1.96.

The following formula is used to compute the minimum sample size
required to estimate the population mean μ within the required
margin of error:

n >= (zc *σ/E)^2

n = (1.96 * 13.5/3)^2

n = 77.79

sample size for 95% CI is 78

The critical value for significance level, α = 0.01 is 2.58.

The following formula is used to compute the minimum sample size
required to estimate the population mean μ within the required
margin of error:

n >= (zc *σ/E)^2

n = (2.58 * 13.5/3)^2

n = 134.79

for 99% CI, sample size = 135

The lower the confidence level the smaller the sample
size.

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