Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and proportions of each group answering yes'' are given below:
Pop. 1: n1=83, p?1=0.714; Pop. 2: n2=93, p?2=0.632
Suppose that the data yields (-0.0641, 0.2281) for a confidence interval for the difference p1?p2 p 1 ? p 2 of the population proportions. What is the confidence level? (Give your answer in terms of percentages.)
Given : n1=83 n2=93 p1=0.714 p2=0.632
The confidence interval is (-0.0641,0.2281)
The pooled estimate is ,
Q=1-P=0.3293
The margin of error is , E=[Upper limit - Lower limit]\2 = [0.2281-(-0.0641)]\2=0.1461
Therefore ,
From normal probability table ,
Therefore , the confidence level is 96%.
Get Answers For Free
Most questions answered within 1 hours.