Let x be a binomial random variable with n = 25 and the probability of failure is 0.4. Using the normal distribution to approximate the binomial, determine the probability that more than 12 successes will occur.
A. 0.8461
B. 0.1539
C. 0.9192
D. 0.0329
Solution :
Given that,
Using binomial distribution,
= n * p = 25 * 0.4 = 10
= n * p * q = 25 * 0.4 * 0.6 = 2.4495
Using continuity correction ,
P(x > 12.5) = 1 - P(x < 12.5)
= 1 - P((x - ) / < (12.5 - 10) / 2.4495)
= 1 - P(z < 1.02)
= 1. - 0.8461
= 0.1539
Probability = 0.1539
Option B) is correct .
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