In a sample of 30 lizards, we find an average of 5 nematodes per specimen with a standard deviation of 3. About how many of our lizards should we expect to be infected with 2 nematodes?
Let X be the number of nematods per specimen.
Mean of X = 5
Standard Deviation of X = 3
The probability that X will be 2 is given by
Applying the continuity correction, we can write the above probability as
Hence, expected number of lizards to be affected by 2 nematods
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