Question

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 11 nursing students from Group 1 resulted in a mean score of 65 with a standard deviation of 4.7. A random sample of 16 nursing students from Group 2 resulted in a mean score of 74 with a standard deviation of 2.5. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 represent the mean score for Group 1 and μ2 represent the mean score for Group 2. Use a significance level of α=0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 2 of 4: Compute the value of the t test statistic. Round your answer to three decimal places.

Compute the value of the t test statistic. Round your answer to three decimal places.

Determine the decision rule for rejecting the null hypothesis H0H0. Round your answer to three decimal places.

State the test's conclusion.

Answer 1

The statistical software output for this problem is:

Hence,

Step - 2: t test statistic = -6.477

Step - 3: Decision rule: Reject Ho if t < -1.316

Step - 4: Reject Null Hypothesis