Question

An equilateral triangle has sides 6cm long. What is the probability that a point chosen at...

An equilateral triangle has sides 6cm long. What is the probability that a point chosen at random in the triangle is within 1 cm of a corner?

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Answer #1

Probability[ a point chosen at random in the triangle is within 1 cm of a corner ]
= Area within 1 cm of a corner / Area of triangle

Area of equilateral triangle of side a =

For a = 6

Area of triangle =

Area within 1 cm of a corner = 3*area of sector with angle 60 degree and radius 1 cm (since, there are three ends of the triangle which we have to take into consideration)

Area within 1 cm of a corner =

Probability[ a point chosen at random in the triangle is within 1 cm of a corner ] = 3.14/15.59

Probability[ a point chosen at random in the triangle is within 1 cm of a corner ] = 0.2014

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