An equilateral triangle has sides 6cm long. What is the probability that a point chosen at random in the triangle is within 1 cm of a corner?
Probability[ a point chosen at random in the triangle is within
1 cm of a corner ]
= Area within 1 cm of a corner / Area of triangle
Area of equilateral triangle of side a =
For a = 6
Area of triangle =
Area within 1 cm of a corner = 3*area of sector with angle 60 degree and radius 1 cm (since, there are three ends of the triangle which we have to take into consideration)
Area within 1 cm of a corner =
Probability[ a point chosen at random in the triangle is within 1 cm of a corner ] = 3.14/15.59
Probability[ a point chosen at random in the triangle is within 1 cm of a corner ] = 0.2014
please upvote
Get Answers For Free
Most questions answered within 1 hours.