The mean height of women in a country (ages 20minus 29) is 63.6 inches. A random sample of 60 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume sigma equals2.84 . The probability that the mean height for the sample is greater than 64 inches is
Given,
Mean = = 63.6 inches
Standard deviation = = 2.84 inches
Sample size = n = 60
According to the Central Limit Theorem.
Let Z = (X - ) /( /sqrt(n)) is a standard normal random variable.
P(X > 64) =P((X - ) /(/sqrt(n)) > (64 -) /(/sqrt(n)))
P( X > 64) = P( Z > (64 - 63.6)/(2.84/sqrt(60)))
P(X > 64)= P(Z > 1.09)
P(X > 64) = 1 - P( Z < 1.09)
P( X > 64) = 1 - 0.8621
P(X > 64) = 0.1379
The probability that the mean height for the sample is greater than 64 inches is 0.1379
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