Question

Assume that when adults with smartphones are randomly selected, 64% use them in meetings or classes. If 88 adult smartphone users are randomly selected, find the probability that exactly 44 of them use their smartphones in meetings or classes. The probability is ____? Round to four decimal places as needed.

Answer #1

it is a binomial probability distribution, because there is
fixed number of trials,

only two outcomes are there, success and failure

trails are independent of each other

and probability is given by

P(X=x) = C(n,x)*p^{x}*(1-p)^{(n-x)} |

where

Sample size , n = 88

Probability of an event of interest, p = 0.64

-------------------

P ( X = 44 ) = C(88,44) * 0.64^44 *
(1-0.64)^44 **=
0.0023(answer)**

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1)
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use them in meetings or classes. If 10 adult smartphone users are
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as needed)
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