pH measurements of a chemical solutions have mean 6.8 with standard deviation 0.04. Assuming all pH measurements of this solution follow a normal distribution, find the probability of selecting a pH measurement at random that reads below 6.68 OR above 6.88 without using the LSND program. (Write the answer in decimals)
Solution :
Given that ,
mean = = 6.8
standard deviation = = 0.04
P( x < 6.68 or x > 6.88 )
= 1 - P( 6.68 < x < 6.88)
= 1 - P((6.68 - 6.8)/ 0.04) < (x - ) / < (6.88 -6.8) / 0.04) )
= 1 - P(-3 < z < 2)
= 1 - (P(z < 2) - P(z < -3))
= 1 - ( 0.9772 - 0.0013 ) Using standard normal table,
Probability = 0.0241
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