Let X~N(219;23) find:
P(166 < X < 232)
Solution :
Given that ,
mean = = 219
standard deviation = = 23
X~N (219;23)
P(166 < x < 232) = P[(166 - 219)/ 23) < (x - ) / < (232 - 219) / 23) ]
= P(-2.3043 < z < 0.5652)
= P(z < 0.5652) - P(z < -2.3043)
= 0.714 - 0.0106
= 0.7034
P(166 < x < 232) = = 0.7034
Get Answers For Free
Most questions answered within 1 hours.