Question

Let X~N(219;23) find: P(166 < X < 232)

Let X~N(219;23) find:

P(166 < X < 232)

Math   Statistics-And-Probability   
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Homework Answers

Answer #1

Solution :

Given that ,

mean = = 219

standard deviation = = 23

X~N (219;23)

P(166 < x < 232) = P[(166 - 219)/ 23) < (x - ) /  < (232 - 219) / 23) ]

= P(-2.3043 < z < 0.5652)

= P(z < 0.5652) - P(z < -2.3043)

= 0.714 - 0.0106

= 0.7034

P(166 < x < 232) = = 0.7034

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