P (5 or odd #5)
P (5 and odd#5)
P( 1 or 2)
Roll two fair dice (? ) white and red . Find P ( sum of 7 on the two dice)
P ( sum of 6 in the two dice)
Show the calculations.
Roll two fair dice (? ) white and red . Find P ( sum of 7 on the two dice)
P ( sum of 6 in the two dice)
Show the calculations.
Total number of possible outcomes when we roll two dice are 6*6 = 36
Possible outcomes of getting sum of 7 on the two dice are (1, 6); (2,5); (3,4); (4,3); (5,2); (6,1) which are equal to 6
So required probability = 6/36 = 1/6 = 0.166667
2) Let's find P ( sum of 6 in the two dice)
Possible outcomes of getting sum of 6 on the two dice are (1, 5); (2,4); (3,3); (4,2); (5,1) which are equal to 5
So required probability = 5/36 = 1/6 = 0.138889
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