Question

A statistics student made the following grades on the first 6 tests: 76, 82, 92, 95, 92, 86. The total number of tests for the semester is 7. If the median score for the whole semester was 92, what could not have been the score of the last test?

a. 77

b.92

c.93

d. 94

e.96

A commuter travels many miles to work each morning. She has timed this trip 5 times during the last month. The time (in minutes) required to make this trip was 34, 39, 41, 35, and 41. The mean time (in minutes) required for this trip was _______.

a.35

b.41

c. 37.5

d. 38

e. 35.5

The ages of students in a class have been put into the frequency distribution below.
age number of students

18 3

19 5

20 28

21 4

What is the standard deviation for this (population) set of data?

a. 0.494

b. 0.703

c. 1.12

d. 1.25

e. 1.35

A commuter travels many miles to work each morning. She has timed this trip 5 times during the last month. The time (in minutes) required to make this trip was 44, 39, 41, 35, and 41. What is the mean absolute deviation for this sample data?

a. 0

b. 12

c. 3

d. 2.4

e. 1.2

A commuter travels many miles to work each morning. She has timed this trip 5 times during the last month. The time (in minutes) required to make this trip was 38, 33, 36, 47, and 41. What is the variance for this sample data?

a. 28.5

b. 11

c. 22.8

d. 5.34

e. 4.77

Answer 1

A statistics student made the following grades on the first 6 tests: 76, 82, 92, 95, 92, 86. The total number of tests for the semester is 7. If the median score for the whole semester was 92, what could not have been the score of the last test?

Answer)

Median is the middlemost data value of arranged data (in ascending order

Let the last score be X

72, 82, 86, 92, 92, 95, X

So, X can be any thing greater than 92

But not less than 92

So 77 cannot be the last value

2)

A commuter travels many miles to work each morning. She has timed this trip 5 times during the last month. The time (in minutes) required to make this trip was 34, 39, 41, 35, and 41. The mean time (in minutes) required for this trip was

Mean = sum of the observations/number of observations

Mean = (34+39+41+35+41)/5 = 38