Question

The mean income per person in the United States is $45,000, and the distribution of incomes follows a normal distribution. A random sample of 17 residents of Wilmington, Delaware, had a mean of $55,000 with a standard deviation of $8,500. At the 0.100 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average?

- State the null hypothesis and the alternate hypothesis.

- State the decision rule for 0.100 significance level.
**(Round your answer to 3 decimal places.)**

- Compute the value of the test statistic.
**(Round your answer to 2 decimal places.)**

- Is there enough evidence to substantiate that residents of Wilmington, Delaware, have more income than the national average at the 0.100 significance level?

Answer #1

The mean income per person in the United States is $39,500, and
the distribution of incomes follows a normal distribution. A random
sample of 16 residents of Wilmington, Delaware, had a mean of
$45,500 with a standard deviation of $9,800. At the 0.010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.010 significance level....

The mean income per person in the United States is $37,500, and
the distribution of incomes follows a normal distribution. A random
sample of 12 residents of Wilmington, Delaware, had a mean of
$46,500 with a standard deviation of $9,000. At the 0.010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.010 significance level....

The mean income per person in the United States is $37,000, and
the distribution of incomes follows a normal distribution. A random
sample of 11 residents of Wilmington, Delaware, had a mean of
$43,000 with a standard deviation of $8,800. At the 0.025 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.025 significance level....

The mean income per person in the United States is $38,000, and
the distribution of incomes follows a normal distribution. A random
sample of 13 residents of Wilmington, Delaware, had a mean of
$48,000 with a standard deviation of $9,200. At the 0.100 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.100 significance level....

The mean income per person in the United States is $37,500, and
the distribution of incomes follows a normal distribution. A random
sample of 12 residents of Wilmington, Delaware, had a mean of
$46,500 with a standard deviation of $9000. At the .010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
(a) State the null hypothesis and the alternate hypothesis.
H0: u is less than or equal...

A United Nations report shows the mean family income for Mexican
migrants to the United States is $26,450 per year. A FLOC (Farm
Labor Organizing Committee) evaluation of 23 Mexican family units
reveals a mean to be $37,190 with a sample standard deviation of
$10,700. Does this information disagree with the United Nations
report? Apply the 0.01 significance level.
a.
State the null hypothesis and the alternate hypothesis.
H0: μ =
H1: μ ≠
b.
State the decision...

A personnel director in a particular state claims that the mean
annual income is greater in one of the state's counties (county
A) than it is in another county (county B). In County A, a random
sample of 13 residents has a mean annual income of $42,000 and a
standard deviation of $8800. In County B, a random sample of 11
residents has a mean annual income of $37,700 and a standard
deviation of $5700. At At alphaαequals= 0.025 answer...

The mean annual incomes of certified welders are normally
distributed with the mean of $75,000 and a population standard
deviation of $3,500. The ship building association wishes to find
out whether their welders earn more or less than $75,000 annually.
The alternate hypothesis is that the mean is not $75,000. If the
level of significance is 0.01, what is the critical value?

The mean annual incomes of certified welders are normally
distributed with the mean of $75,000 and a population standard
deviation of $3,500. The ship building association wishes to find
out whether their welders earn more or less than $75,000 annually.
The alternate hypothesis is that the mean is not $75,000. If the
level of significance is 0.01, what is the critical value?
±2.576
−2.576
±1.645
+1.645

The amount of water consumed each day by a healthy adult follows
a normal distribution with a mean of 1.44 liters. A health campaign
promotes the consumption of at least 2.0 liters per day. A sample
of 10 adults after the campaign shows the following consumption in
liters:
1.80
1.94
1.70
1.50
1.64
1.40
1.64
1.70
1.66
1.54
At the 0.100 significance level, can we conclude that water
consumption has increased? Calculate and interpret the
p-value.
State the null hypothesis...

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