A particular lake is known to be one of the best places to catch a certain type of fish. In this table, x = number of fish caught in a 6-hour period. The percentage data are the percentages of fishermen who caught x fish in a 6-hour period while fishing from shore.
x | 0 | 1 | 2 | 3 | 4 or more |
% | 42% | 37% | 14% | 6% | 1% |
(b) Find the probability that a fisherman selected at random
fishing from shore catches one or more fish in a 6-hour period.
(Round your answer to two decimal places.)
(c) Find the probability that a fisherman selected at random
fishing from shore catches two or more fish in a 6-hour period.
(Round your answer to two decimal places.)
(d) Compute μ, the expected value of the number of fish caught per
fisherman in a 6-hour period (round 4 or more to 4). (Round your
answer to two decimal places.)
μ = fish
(e) Compute σ, the standard deviation of the number of fish caught per fisherman in a 6-hour period (round 4 or more to 4). (Round your answer to three decimal places.)
σ = fish
a)
P(X >= 1) = 1 - P(X = 0)
= 1 - 0.42
= 0.58
b)
P(X >= 2) = 1 - P(X < = 1 )
= 1 - [ P( X = 0) + P(X = 1) ]
= 1 - [ 0.42 + 0.37 ]
= 0.21
c)
E(X) = = X * P(X)
= 0 * 0.42 + 1 * 0.37 + 2 * 0.14 + 3 * 0.06 + 4 * 0.01
= 0.87
d)
Standard deviation = sqrt [ X2 * P(X) - 2 ]
= sqrt [ 02 * 0.42 + 12 * 0.37 + 22 * 0.14 + 32 * 0.06 + 42 * 0.01 - 0.872 ]
= 0.934
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