Question

1. Of 1000 randomly selected cases of lung cancer, 823 resulted in death. Is there sufficient...

1. Of 1000 randomly selected cases of lung cancer, 823 resulted in death. Is there sufficient evidence to say the true proportion of lung cancer deaths is different than 85% at a significance level of 5%. a) Are the normality assumptions satisfied? Explain why.

b) State hypotheses.

c) Calculate the test statistic

d) What is/are the critical value(s)?

e) What is your decision?

f) What is the conclusion/interpretation of this decision?

Homework Answers

Answer #1

a)

np = 1000 * 0.85 = 850 >= 10

n(1-p) = 1000 * (1-0.85) = 150 >= 10

Since np>= 10 and n(1-p) >= 10 , the normality assumptions are satisfied.

b)

H0: p = 0.85

Ha: p 0.85

c)

Sample proportion = 823 / 1000 = 0.823

Test statistics

z = - p / sqrt( p( 1 - p) / n)

= 0.823 - 0.85 / sqrt( 0.85 * ( 1 - 0.85) / 1000)

= -2.39

d)

From Z table, critical values at 0.05 level = -1.96 , 1.96

e)

Since test statistics falls in rejection region, that is test statistics value < -1.96

so we have sufficient evidence to reject H0.

f)

We conclude at 0.05 level that we have enough evidence to support the claim that the true proportion

of lung cancer deaths is different than 85%.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A study investigated whether regular mammograms resulted in fewer deaths from breast cancer over a period...
A study investigated whether regular mammograms resulted in fewer deaths from breast cancer over a period of 15 years. Among 30,579 women who never had​ mammograms, 191 died of breast​ cancer, while only 141 of 30,152 who had undergone screening died of breast cancer. ​a) Do these results suggest that mammograms may be an effective screening tool to reduce breast cancer​ deaths? ​b) If your conclusion is​ incorrect, which type of error did you​ commit? Determine the test statistic. z=...
Problem: Proportion of ”Cured” Cancer Patients: How Does Canada Compare with Europe? Lung cancer remains the...
Problem: Proportion of ”Cured” Cancer Patients: How Does Canada Compare with Europe? Lung cancer remains the leading cause of cancer death for both Canadian men and women, responsible for the most potential years of life lost to cancer. Lung cancer alone accounts for 28% of all cancer deaths in Canada (32%. in Quebec). Most forms of lung cancer start insidiously and produce no apparent symptoms until they are too far advanced. Consequently, the chances of being cured of lung cancer...
A telephone survey of 1000 randomly selected US adults found that 29% of them say they...
A telephone survey of 1000 randomly selected US adults found that 29% of them say they believe in ghosts. Does this provide evidence that more than 1 in 4 US adults believe in ghosts? Clearly show all details of the test (including hypotheses). Be sure to show all of your statistical methods (calculations, simulation & sketches) and explain your conclusion as well as what your p-value “says” to us in this context. Details of all steps of your hypothesis test...
You wish to test the following claim ( H 1 ) at a significance level of...
You wish to test the following claim ( H 1 ) at a significance level of α = 0.005 . H o : p = 0.15 H 1 : p > 0.15 You obtain a sample of size n = 412 in which there are 85 successful observations. What is the critical value for this test? (Report answer accurate to three decimal places.) critical value = What is the test statistic for this sample? (Report answer accurate to three decimal...
The data below represent the weight losses for people on three different exercise programs. Exercise A...
The data below represent the weight losses for people on three different exercise programs. Exercise A Exercise B Exercise C xbar = 6.7 xbar = 4.16 xbar = 6,46 s = 2.94 s =2.94 s =1.58 n = 5 n = 5 n = 5 At the 1% significance level, do the data provide sufficient evidence that a difference exists in the true mean weight loss produced by the three exercise programs? Perform a critical value test. (Assume all assumptions...
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong...
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong to not report all income on tax returns. Use a 0.01 significance level to test the claim that 75% of adults say that it is morally wrong to not report all income on tax returns. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method. Use the normal...
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong...
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong to not report all income on tax returns. Use a 0.05 significance level to test the claim that 75​% of adults say that it is morally wrong to not report all income on tax returns. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method. Use the normal...
In a sample of 160 children selected randomly from one town, it is found that 32...
In a sample of 160 children selected randomly from one town, it is found that 32 of them suffer from asthma. At the 0.05 significance level, suppose we want to test if these data provide sufficient evidence to conclude the proportion of all children in the town who suffer from asthma is different from 14%? A. State the null and alternative hypotheses. (b) Based on the sample information, calculate the test statistic. (c) Find the P-value. (d) Test the hypothesis...
The heights of 12 randomly selected women are given below (in inches). The sign test at...
The heights of 12 randomly selected women are given below (in inches). The sign test at the 0.005 significance level will be used to test the claim that the population median is greater than 64 inches. 64 66.6 64 67.5 60.6 66.1 65.1 65.1 64 61.7 65.8 61.1 (a) What is the value of the test statistic used in this sign test? (b) What is the critical value in this sign test? (c) What is the correct conclusion of this...
In a sample of 165 children selected randomly from one town, it is found that 30...
In a sample of 165 children selected randomly from one town, it is found that 30 of them suffer from asthma. At the 0.05 significance level, do the data provide sufficient evidence to conclude that the percentage of all children in the town who suffer from asthma is different from 11%? Use the P-value approach. a) State the null and alternative hypotheses symbolically. b) Which test procedure is appropriate to perform the required hypothesis test? Please check the assumptions. c)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT