Question

Suppose 54% of the students in a university are baseball players.

If a sample of 662 students is selected, what is the probability that the sample proportion of baseball players will be greater than 58%? Round your answer to four decimal places.

Answer 1

Solution :

Given that,

p = 0.54

q = 1 - p =1-0.54=0.46

n = 662

= p =0.54

=  [p( 1 - p ) / n] = [(0.54*0.46) /662 ] = 0.0194

P( >0.58 ) = 1 - P( <0.58 )

= 1 - P(( - ) / < (0.58 -0.54) /0.0194 )

= 1 - P(z < 2.06)

Using z table

= 1 -0.9803

=0.0197

probability=0.0197