Question

Suppose the following table was generated from the sample data of 20 campuses relating the total number of crimes committed to the number of police officers on campus and if the college or university is private.

	Coefficients	Standard Error	t-stat	P-Value
Intercept	559.505805	19.468953	28.738361	0.000000
# of officers	-6.845383	0.631437	-10.840960	0.000000
Private (1 if private, 0 otherwise)	-55.712802	8.049521	-6.921257	0.000002

Step 1 of 2: In this regression equation, what is the intercept value for colleges or universities that are public? Enter your answer in the space provided. Do not round your answer.

Step 2 of 2: In this regression equation, what is the intercept value for colleges or universities that are private? Enter your answer in the space provided. Do not round your answer.

Answer 1

Looking at the coefficient column from the table, we have here:
Intercept = 559.505805

And the dummy variable for Private: -55.712802

Step 1: The intercept value for colleges of universities that are public is computed here as:
= Intercept + 0*Private

= 559.505805

Therefore 559.505805 is the required intercept for colleges or universities that are public.

Step 2: We are given here that the Private is 1 for private university, therefore the intercept here is computed as:
= Intercept + Private

= 559.505805 - 55.712802

= 503.793003

Therefore 503.793003 is the required intercept here.