Question

50 Patients in a hospital are interviewed. 15 have fever, 10 had diarrhea and 5 had...

50 Patients in a hospital are interviewed. 15 have fever, 10 had diarrhea and 5 had both.

What is the probability that after picking one randomly, it has one of both illness?

What is the probability that after picking one randomly, it doesnt have fever?

What is the probability that after picking one randomly, it doesnt have an illness?

Homework Answers

Answer #1

50 patients are interviewed .

Out of them 15 have fever , 10 have diarrhea and 5 had both.

Using,

Probability = Favourable Outcomes/Total Outcomes

A. P(one of both illeness) = P(Fever) + P(diarrhea) - P(both)

= 15/50 + 10/50 - 5/50

= 20/50 or 0.4

Thus, there is 0.4 Probability that a randomly selected patient is having one of these illness.

B.P( not fever patient) = 1 - P(fever)

= 1 - 15/50

= 35/50 or 0.7

Thus, there is 0.7 Probability that a randomly selected patient is not having fever.

C. P (neither fever nor diarrhea) = 1 - P( fever or diarrhea)

= 1 - 0.4

= 0.6

Thus, there is 0.6 Probability that a randomly selected patient is not having these diseases.

Please like the answer,Thanks!

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