Question

A diet doctor claims that the average North American is more than 20 pounds overweight. To...

A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 20 North Americans was weighed, and the difference between their actual and ideal weights was calculated.

The data is listed below:

16 23 18 41 22 18 23 19 22 15

18 35 16 15 17 19 23 15 16 26

The sample statistics are: ?̅= 20.85, ? = 6.76.

Can we infer, at the 5% significance level, that the doctor’s claim is true?

Assume the required conditions are satisfied

H0 : _______________________

H1 : _______________________

Conclusion: Reject H0 Accept H0

Homework Answers

Answer #1

Answer: ---- Date: ---7/7/2019

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A diet doctor claims that the average North American is more than 20 pounds overweight. To...
A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 20 North Americans was weighed, and the difference between their actual and ideal weights was calculated. The data is listed below: 16 23 18 41 22 18 23 19 22 15 18 35 16 15 17 19 23 15 16 26 The sample statistics are: ?̅ = 20.85, ? = 6.76. Can we infer, at the 5%...
A diet doctor claims that the average North American is more than 20 pounds overweight. To...
A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 30 North Americans was weighted, and the difference between their actual weight and their ideal weight was calculated. The sample mean is 20.85 pounds and the sample standard deviation is 3.76 pounds. Find the p-value for this hypothesis test. H_{a} \:: \mu >20 H a : μ > 20 pounds
A doctor discovers a particular disease and determines the life expectancy is not good. He gathers...
A doctor discovers a particular disease and determines the life expectancy is not good. He gathers the data for his patents and posts it in the table below. The claims that the average life expectancy once the disease presents itself is less than 15 days. Check his claim and make an appropriate report about your findings Patient Days till passing 1 24 2 23 3 13 4 20 5 10 6 18 7 13 8 14 9 24 10 25...
We want to compare the average gas mileage of American-made cars vs. Japanese-made cars. The claim...
We want to compare the average gas mileage of American-made cars vs. Japanese-made cars. The claim is that the Japanese cars and American cars do not get the same gas mileage. Use the list data below to test the hypothesis that the Japanese cars and American cars do not get the same gas mileage. The American cars are in list1 and the Japanese cars in list2 below We do not know whether the mileages are normally distributed or not, but...
a sample have 10 students the average score in math is less than the average in...
a sample have 10 students the average score in math is less than the average in english x1= test scores in math x2= test scores in english assume the scores follow normal distribution let u1 be the population mean of math scored let u2 be the population mean of english score the score are given below student. math. english 1. 18. 22 2. 22. 24 3. 19. 16 4. 23. 19 5. 20. 21 6. 18. 18 7. 16. 17...
Travel-Times: There are three different ways I can go to work in the morning. I want...
Travel-Times: There are three different ways I can go to work in the morning. I want to see if there is a difference in mean travel-times between the three different ways. The sample data is depicted below. The second table displays results from an ANOVA test on this data with software. I claim there is a difference in mean travel-times between the three different routes. Travel Times in Minutes x Interstate 23   24     22     22     21     20     22.0   Route 15...
1) The sample mean and standard deviation from a random sample of 22 observations from a...
1) The sample mean and standard deviation from a random sample of 22 observations from a normal population were computed as x¯=40 and s = 13. Calculate the t statistic of the test required to determine whether there is enough evidence to infer at the 7% significance level that the population mean is greater than 37. Test Statistic= 2) The contents of 33 cans of Coke have a mean of x¯=12.15 and a standard deviation of s=0.13. Find the value...
Is there an association between patient BMI and cholesterol level at screening? Consider overweight, normal and...
Is there an association between patient BMI and cholesterol level at screening? Consider overweight, normal and underweight categories for BMI. Do a Chi-Square. I am having trouble finding the test statistics. I picked the level of significance to be 5%. Patient ID Drug Sex Age Height BMI Weight Cholesterol 1 B F 22 67.13 21.52787 138 197 2 B M 22 63 20.36911 115 181 3 B F 22 72 25.76582 190 190 4 A M 22 69 16.98068 115...
Administrators want to know the effectiveness of the Orange Grove Elementary reading program. The average reading...
Administrators want to know the effectiveness of the Orange Grove Elementary reading program. The average reading comprehension score is 22 for children of comparative age. The data below are reading comprehension scores from a sample of children from Orange Grove Elementary. Scores range from 0 - 40 with higher scores indicating better reading comprehension. What can be concluded with α = 0.05? id reading 35 36 37 38 39 40 41 42 43 44 45 10 11 12 13 14...
Administrators are sure about the ineffectiveness of the Apple Orchard Preschool reading program. The average reading...
Administrators are sure about the ineffectiveness of the Apple Orchard Preschool reading program. The average reading comprehension score is 20 for children of comparative age. The data below are reading comprehension scores from a sample of children from Apple Orchard Preschool. Scores range from 0 - 40 with higher scores indicating better reading comprehension. What can be concluded with α = 0.05? id reading 35 36 37 38 39 40 41 42 43 44 45 10 11 12 13 14...