A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 1313 nursing students from Group 1 resulted in a mean score of 60.860.8 with a standard deviation of 4.64.6. A random sample of 99 nursing students from Group 2 resulted in a mean score of 73.973.9 with a standard deviation of 6.36.3. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1μ1 represent the mean score for Group 1 and μ2μ2 represent the mean score for Group 2. Use a significance level of α=0.01α=0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed.
Step 1: State the null and alternative hypotheses for the test.
Step 2 of 4: Compute the value of the t test statistic. Round your answer to three decimal places
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places.
Reject Ho if (t, I t I) (<,>) ____
Step 4 of 4: State the test's conclusion.
A. Reject Null Hypothesis
B. Fail to Reject Null Hypothesis
step 1:
Ho:μ1-μ2 |
|
0 | |
Ha: μ1-μ2 | < | 0 |
step 2:
test stat t =(x1-x2-Δo)/Se= | -5.652 |
Step 3 of 4:
Reject Ho if t < -2.528
step 4:
A. Reject Null Hypothesis
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