Question

In a software company, 30% of the employees are from College-A, 35% are from College-B, 20% are from College-C and 15% are from College-D. The percentage of employees from these colleges, who are comfortable in ML programming are 20%, 90%,60% and 70% respectively. An employee is selected at random

(a). What is the probability that the employee is comfortable in ML programming?

(b) The recruitment team wants to know the inputs from you based on this data, so that they can prioritize the next recruitment cycle to select people who are comfortable in ML programming.

Answer 1

	Comfortable	Not Comfortable	Total
College A	20% of 30% = 0.06	80% of 30% = 0.24	0.3
College B	90% of 35% = 0.315	10% of 35% = 0.035	0.35
College C	60% of 20% = 0.12	40% of 20% = 0.08	0.2
College D	70% of 15% = 0.105	30% of 15% = 0.045	0.15
Total	0.6	0.4	1

Using Independent condition,

P(A and B) = P(A)*P(B)

a) P( comfortable employee) = P(comfortable employee and from College A) + P( comfortable employee and from College B) + P(comfortable employee and from College C) + P(comfortable employee and from College D)

= 0.06 + 0.315 + 0.12 + 0.105

= 0.6

Thus , there is 0.6 Probability that an employee is comfortable in ML programming.

b) The recruitment team should hire higher number from College B since , more than half of the comfortable people are from college B only. (0.315 out of 0.6) . And 90% of college B students are comfortable.

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