Question

The data show the bug chirps per minute at different temperatures. Find the regression​ equation, letting the first variable be the independent​ (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of

3000

chirps per minute. Use a significance level of 0.05. What is wrong with this predicted​ value?

Chirps in 1 mi	841	838	1012	787	1234	1185
Temperature ​(degrees°​F)	74.37	74.77	78.77	64.56	93	90.7

What is the regression​ equation?

y =25.96+0.05430x

​

What is the best predicted temperature for a time when a bug is chirping at the rate of

3000

Is ? F

​(Round to one decimal place as​ needed.)

Answer 1

from above: regression equation: y^ =26.17+0.05412x

2)

correlation coefficient r=

Sxy/(√Sxx*Syy) =

0.9646

(since correlation coefficient >critical value we can use regression equation for prediction)

best predicted temperature =26.17+0.05412*3000 =188.5