Question

The Pew Internet and American Life Project reports that young people ages 12-17 send a mean...

The Pew Internet and American Life Project reports that young people ages 12-17 send a mean of 60 text messages per day. A random sample of 25 young people showed a sample mean of 69 texts per day with a sample standard deviation of 18 messages.

(a) Using a significance level of α = 0.01, test whether the population mean number of text messages per day differs from 60. Make sure you state your hypotheses and your critical region.

(b) Using a significance level of α = 0.01, test whether the population mean number of text messages per day is greater than 60. Make sure you state your hypotheses and your critical region.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we...
textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year olds to see if their mean number of daily texts differs from the mean for 18–24 year olds reported by TextRequest. a. State the null and alternative hypotheses we should use to test whether the popu-lation mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds....
A report states that adults 18- to 24- years-old send and receive 128 texts every day....
A report states that adults 18- to 24- years-old send and receive 128 texts every day. Suppose we take a sample of 25- to 34- year-olds to see if their mean number of daily texts differs from the mean for 18- to 24- year-olds. A. State the null and alternative hypotheses we should use to test whether the population mean daily number of texts for 25- to 34-year-olds differs from the population daily mean number of texts for 18- to...
Test the claim that the mean time Americans send watching TV per day is 4.4 hours...
Test the claim that the mean time Americans send watching TV per day is 4.4 hours at the 0.01 level of significance. A random sample of 360 people had a mean time of 4.05 hours of viewing per day. Assume that the population watching times are normally distributed with standard deviation 1.08 hours. Explain how you arrived at your answer by using the appropriate distribution curve to show the acceptance region and the critical region.
For the United States, the mean monthly Internet bill is $64.79 per household (CNBC, January 18,...
For the United States, the mean monthly Internet bill is $64.79 per household (CNBC, January 18, 2012). A sample of 50 households in a southern state showed a sample mean of $60.63. Use a population standard deviation of σ = $5.60 Formulate hypotheses at the α = 0.01 significance level for a test to determine whether the sample data support the conclusion that the mean monthly Internet bill in the southern state is less than the national mean of $64.79....
America's young people are heavy Internet users; 87% of Americans ages 12 to 17 are Internet...
America's young people are heavy Internet users; 87% of Americans ages 12 to 17 are Internet users (The Cincinnati Enquirer, February 7, 2006). MySpace was voted the most popular website by 9% in a sample survey of Internet users in this age group. Suppose 1,600 youths participated in the survey. What is the margin of error, and what is the interval estimate of the population proportion for which MySpace is the most popular website? Use a 95% confidence level and...
2. Last year the government made a claim that the average income of the American people...
2. Last year the government made a claim that the average income of the American people was $33,950. However, a sample of 50 people taken recently showed an average income of $34,076 with a population standard deviation of $324. Is the government’s estimate too low? Conduct a significance test to see if the true mean is more than the reported average. Use a significance level of 0.01. A. Hypotheses: B. Test Statistic C. Critical Value P – value: _______________ D....
6.The expected mean of a normal population is 100, and its standard deviation is 12. A...
6.The expected mean of a normal population is 100, and its standard deviation is 12. A sample of 49 measurements gives a sample mean of 96. Using the α = 0.01 level of significance a test is to be made to decide between “population mean is 100” or “population mean is different than 100.” a) State null H0. b) What conclusion can be drawn at the given level of significance α = 0.01. c) What conclusion can be drawn if...
6. The expected mean of a normal population is 100, and its standard deviation is 12....
6. The expected mean of a normal population is 100, and its standard deviation is 12. A sample of 49 measurements gives a sample mean of 96. Using the α = 0.01 level of significance a test is to be made to decide between “population mean is 100” or “population mean is different than 100.” a) State null H0. b) What conclusion can be drawn at the given level of significance α = 0.01. c) What conclusion can be drawn...
The mean hourly wage for employees in goods-producing industries is currently $24.57. Suppose we take a...
The mean hourly wage for employees in goods-producing industries is currently $24.57. Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value. Conduct a hypothesis test to determine if the...
.6 The expected mean of a normal population is 100, and its standard deviation is 12....
.6 The expected mean of a normal population is 100, and its standard deviation is 12. A sample of 49 measurements gives a sample mean of 96. Using the α = 0.01 level of significance a test is to be made to decide between “population mean is 100” or “population mean is different than 100.” a) State null H0. b) What conclusion can be drawn at the given level of significance α = 0.01. c) What conclusion can be drawn...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT