Question

For the following information, determine whether a normal sampling distribution can be used, where p is the population proportion,α is the level of significance, ModifyingAbove p with caretp is the sample proportion, and n is the sample size. If it can be used, test the claim. Claim:

p>0.29

α=0.08

Sample statistics:

ModifyingAbove p with caretpequals=0.36

n=375

Answer #1

Null hypothesis H0: p<=0.29

Alternate hypothesis Ha: p>0.29

phat = 0.36

We will use normal sampling distribution as sample size is greater
than 30

Ztest Stat = (0.36-0.29)/sqrt(0.29*0.71/375) = 2.99

From Z table we found p-value = 0.0014

at alpha = 0.08, we can reject the null hypothesis as p-value is
less than alpha value(0.08<0.0014)

So we can reject the null hypothesis and We have significant
evidence to support the alternative hypothesis.

For the following information, determine whether a normal
sampling distribution can be used, where p is the population
proportion,
alphaα
is the level of significance,
ModifyingAbove p with caretp
is the sample proportion, and n is the sample size. If it can
be used, test the claim.Claim:
pgreater than or equals≥0.47
alphaαequals=0.06
Sample statistics:
ModifyingAbove p with caretpequals=0.40,
nequals=180

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the population proportion p
at the given level of significance alpha using the given sample
statistics. Claim: pnot equals0.29; alphaequals0.01; Sample
statistics: ModifyingAbove p with caretequals0.22, nequals150

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the population proportion p
at the given level of significance alpha using the given sample
statistics. Claim: pnot equals0.24; alphaequals0.01; Sample
statistics: ModifyingAbove p with caretequals0.19, nequals200

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the population proportion p
at the given level of significance
alphaα
using the given sample statistics.Claim:
pnot equals≠0.24;
alphaαequals=0.10;
Sample statistics:
ModifyingAbove p with caretpequals=0.21,
nequals=200
Can the normal sampling distribution be used?
state the null and alternative hypothesis.
determine the critical value.
find the z-test statistic.
what is the result of the test?
Reject
Upper H 0H0.
The data provide sufficient...

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the difference between two
population proportions p 1 and p 2 at the given level of
significance alpha using the given sample statistics. Assume the
sample statistics are from independent random samples. Claim: p
1equalsp 2, alphaequals0.01 Sample statistics: x 1equals27, n
1equals129 and x 2equals32, n 2equals206 Can a normal sampling
distribution be used?

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the difference between two
population proportions p 1 and p 2 at the given level of
significance alpha using the given sample statistics. Assume the
sample statistics are from independent random samples. Claim: p
1equalsp 2, alphaequals0.10 Sample statistics: x 1equals88, n
1equals171 and x 2equals172, n 2equals212

Decide whether the normal sampling distribution can be used. If
it can be used, test the claim about the difference between two
population proportions
p 1p1
and
p 2p2
at the given level of significance
alphaα
using the given sample statistics. Assume the sample statistics
are from independent random samples.
Claim:
p 1p1equals=p 2p2,
alphaαequals=0.010.01
Sample statistics:
x 1x1equals=2323,
n 1n1equals=113113
and
x 2x2equals=103103,
n 2n2equals=179179
a) find the standardized test statistics

Describe the sampling distribution of ModifyingAbove p with
caretp. Assume the size of the population
ism25,000.n=900,p=0.116
Describe the shape of the sampling distribution of
ModifyingAbove p with caretp.
Choose the correct answer below.
The shape of the sampling distribution of
ModifyingAbove p with caretp
is not normal because
n less than or equals 0.05 Upper Nn≤0.05N
and np left parenthesis 1 minus p right parenthesis less than
10.np(1−p)<10.
B.The shape of the sampling distribution of
ModifyingAbove p with caretp
is...

Describe the sampling distribution of
ModifyingAbove p with caretp.
Assume the size of the population is
20 comma 00020,000.
nequals=700700,
pequals=0.2060.206
Describe the shape of the sampling distribution of
ModifyingAbove p with caretp.
Choose the correct answer below.
A.The shape of the sampling distribution of
ModifyingAbove p with caretp
is approximately normal because
n less than or equals 0.05 Upper Nn≤0.05N
and np left parenthesis 1 minus p right parenthesis less than
10.np(1−p)<10.
B.The shape of the sampling distribution of...

Describe the sampling distribution of
ModifyingAbove p with caretp.
Assume the size of the population is
25,000.
nequals=600,
pequals=0.5
Choose the phrase that best describes the shape of the sampling
distribution of
ModifyingAbove p with caretp
below.
A.Not normal because
n less than or equals 0.05 Upper Nn≤0.05N
and np left parenthesis 1 minus p right parenthesis greater than
or equals 10.np(1−p)≥10.
B.Approximately normal because
n less than or equals 0.05 Upper Nn≤0.05N
and np left parenthesis 1 minus p...

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