Question

A random sample of 40 bags of flour is weighed. It is found that the sample...

A random sample of 40 bags of flour is weighed. It is found that the sample mean is 453.08 grams. All weights of the bags of flour have a population standard deviation of 5.42 grams. What is the lower limit of an 80% confidence interval for the population mean weight?
Select one:
A. 452.405 grams
B. 451.983 grams
C. 452.360 grams
D. No solution

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An engineer has conducted an experiment on the weight of bags of sugar that come off...
An engineer has conducted an experiment on the weight of bags of sugar that come off the filling line. A sample of size 50 is collected, and it is found to have a sample mean of 16.147 lbs and a standard deviation of 0.87 lbs. Calculate the 95% Confidence Interval on the weight of the bags of flour, and use it to determine if it is believable that the population mean for the weight of all bags of flour produced...
A statistics instructor randomly selected four bags of​ oranges, each bag labeled 10​ pounds, and weighed...
A statistics instructor randomly selected four bags of​ oranges, each bag labeled 10​ pounds, and weighed the bags. They weighed 9.7​, 9.1​, 9.2​, and 9.3 pounds. Assume that the distribution of weights is Normal. Find a​ 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b below. Part A: Choose the correct interpretation of the confidence interval below​ and, if​ necessary, fill in the answer boxes to complete...
A sample of 15 small bags of Skittles was selected. The mean weight of the sample...
A sample of 15 small bags of Skittles was selected. The mean weight of the sample of bags was 2 ounces and the standard deviation was 0.12 ounces. The population standard deviation is known to be 0.1 ounces. (Assume the population distribution of bag weights is normal) a) Construct a 95% confidence interval estimating the true mean weight of the candy bags. (4 decimal places b) What is the margin of error for this confidence interval? c) Interpret your confidence...
A statistics instructor randomly selected four bags of​ oranges, each bag labeled 10​ pounds, and weighed...
A statistics instructor randomly selected four bags of​ oranges, each bag labeled 10​ pounds, and weighed the bags. They weighed 10.3, 10.2, 10.3, and 10.4 pounds.    Assume that the distribution of weights is Normal. Find a​ 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. a. Choose the correct interpretation of the confidence interval. Is the answer A,B,C or D and the 2 numbers. A.We are​ 95% confident that the sample mean...
From a random sample of 16 bags of chips, sample mean weight is 500 grams and...
From a random sample of 16 bags of chips, sample mean weight is 500 grams and sample standard deviation is 3 grams. Assume that the population distribution is approximately normal. Answer the following questions 1 and 2. 1. Construct a 95% confidence interval to estimate the population mean weight. (i) State the assumptions, (ii) show your work and (iii) interpret the result in context of the problem. 2.  Suppose that you decide to collect a bigger sample to be more accurate....
A process produces bags of refined sugar. The weights of the contents of these bags are...
A process produces bags of refined sugar. The weights of the contents of these bags are normally distributed with a standard deviation of 1.2 ounces. The contents of a random sample of twenty five bags had a mean weight of 19.8 ounces. Find a 98% confidence interval for the true mean weight for all bags of sugar produced by the process. interpret the results
A manufacturer claims that the mean weight of flour in its 32-ounce bags is its 32.1...
A manufacturer claims that the mean weight of flour in its 32-ounce bags is its 32.1 ounces. A T-Test is performed to determine whether the mean weight is actually less than this. The mean weight for a random sample of 45 bags of flour was 30.7 ounces with a standard deviation of 2.5 ounces. Test the claim at the 5% significance level. a) Check the assumptions: b) Hypotheses (State in symbols and in words): Ho: Ha: c) Test Statistic: ___________________...
A manufacturer claims that the mean weight of flour in its 32-ounce bags is 32.1 ounces....
A manufacturer claims that the mean weight of flour in its 32-ounce bags is 32.1 ounces. A T-Test is performed to determine whether the mean weight is actually less than this. The mean weight for a random sample of 45 bags of flour was 30.7 ounces with a standard deviation of 2.5 ounces. Test the claim at the 5% significance level. a) Check the assumptions: b) Hypotheses (State in symbols and in words): Ho: Ha: c) Test Statistic: d) Sketch:...
Bags of a certain brand of potato chips say that the net weight of the contents...
Bags of a certain brand of potato chips say that the net weight of the contents is 35.6 grams. Assume that the standard deviation of the individual bag weights is 5.2 grams. A quality control engineer selects a random sample of 100 bags. The mean weight of these 100 bags turns out to be 33.6 grams. Use this information to answer the questions below. 1. We can use a normal probability model to represent the distribution of sample means for...
1- The accuracy of a potato chip bag filling machine was studied. A simple random sample...
1- The accuracy of a potato chip bag filling machine was studied. A simple random sample of 12 bags had a sample mean fill weight of 8.12 oz. and a sample standard deviation of 0.1 oz. The distribution of the fill weights is assume NORMAL. Find a 99% confidence interval LOWER LIMIT for the population mean fill weight. Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT