Question

In a study of the effectiveness of a fabric device that acts like a support stocking for a weak or damaged heart, 110 people who consented to treatment were assigned at random to either a standard treatment consisting of drugs or the experimental treatment that consisted of drugs plus surgery to install the stocking. After two years, 40% of the 60 patients receiving the stocking had improved and 30% of the patients receiving the standard treatment had improved. (Use a statistical computer package to calculate the P-value. Use p_experimental − p_standard. Round your test statistic to two decimal places and your P-value to four decimal places.)

z	=
P	=

Answer 1

Given data :

n1=60

n2=50

p1=0.40

p2=0.30

Hypothesis :

The pooled sample proportion is

Test statistics:

P value :P value : Is the vaue of the lowets level of singnificance at which we could reject the Null hypothesis H0
Using P value approch ,we reject the null hypothesis

Using Excel P value=1-normsdist(1.09)

=0.1378 >0.5

Result is not significant

Ans :

Z=1.09

P=0.1378