Given that x is a normal variable with mean μ = 48 and standard deviation σ = 6.3, find the following probabilities. (Round your answers to four decimal places.) (
a) P(x ≤ 60)
(b) P(x ≥ 50)
(c) P(50 ≤ x ≤ 60)
Please break down explanation a-c.
Given
X is a Normal variable
mean (μ) = 48
standard deviation (σ) = 6.3
First convert into Z score which is given as
When x= 60
Z =1.90
Now,
P(x ≤ 60) = P(Z ≤ 1.90)
From Z-score table,
P(Z ≤ 1.90) = 0.9713
b)
When x= 50
Z = 0.32
Now,
P(x ≥ 50) = P(Z ≥ 0.32) = 1 - P(Z ≤ 0.32)
From Z-score table, ( table only give the area under the curve below the Z score )
P(Z ≤ 0.32) = 0.6255
Therefore,
P(x ≥ 50) = P(Z ≥ 0.32) = 1 - P(Z ≤ 0.32) =1 - 0.6255 = 0.3745
c)
When x= 50
Z = 0.32
When x= 60
Z =1.90
Now,
P(50 ≤ x ≤ 60) = P(x ≤ 60) - P(x ≤ 50)
=P(Z ≤ 1.90) - P(Z ≤ 0.32)
= 0.9713 - 0.6255
= 0.3458
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