The label on a companies energy drink claims that they contain 250 mg/oz. The mean caffeine concentration of 15 randomly sampled drinks was 267, with a standard deviation of 12.1. Was a two-tailed test used to assess the alternative hypothesis? What is the P-value?
Population mean = = 250
Sample mean = = 267
Sample standard deviation = s = 12.1
Sample size = n = 15
This is a two tailed test.
The null and alternative hypothesis is,
The test statistics,
t = ( - )/ (s/)
= ( 267 - 250 ) / ( 12.1 / 15 )
P- Value = 0.0001
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