A common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight. Suppose that the percentage of no-shows at flight time is 2 %. For a particular flight with 247 seats, a total of 250 tickets were sold. What is the probability that the airline overbooked this flight?
The probability is ___ (Round to four decimal places as needed.)
Well, this is a question of the binomial distribution. Let X be the number of people who show up for the flight.
Then X ~ Binomial(250,1-0.02)
i.e. X ~ Binomial(250,0.98)
We need to find the probability:
P(Flight is overbooked)
=P(X>247)
=P(X>=248)
Hence the answer is:
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