Question

The average time to run the 5K fun run is 20 minutes and the standard deviation...

The average time to run the 5K fun run is 20 minutes and the standard deviation is 2.3 minutes. 7 runners are randomly selected to run the 5K fun run. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of X X ? X X ~ N(,) What is the distribution of ¯ x x¯ ? ¯ x x¯ ~ N(,) What is the distribution of ∑ x ∑x ? ∑ x ∑x ~ N(,) If one randomly selected runner is timed, find the probability that this runner's time will be between 19.696 and 20.996 minutes. For the 7 runners, find the probability that their average time is between 19.696 and 20.996 minutes. Find the probability that the randomly selected 7 person team will have a total time more than 137.9. For part e) and f), is the assumption of normal necessary? NoYes The top 10% of all 7 person team relay races will compete in the championship round. These are the 10% lowest times. What is the longest total time that a relay team can have and still make it to the championship round? minutes

Homework Answers

Answer #1

a)

X ~ N(20,2.3)

b) x¯ ~ N(20 ,0.8693)

c)

∑x ~ N(140 , 6.0852)

d) If one randomly selected runner is timed, find the probability that this runner's time will be between 19.696 and 20.996 minutes.

probability =P(19.696<X<20.996)=P((19.696-20)/2.3)<Z<(20.996-20)/2.3)=P(-0.13<Z<0.43)=0.6675-0.4474=0.2201

e)

probability =P(19.696<X<20.996)=P((19.696-20)/0.869)<Z<(20.996-20)/0.869)=P(-0.35<Z<1.15)=0.874-0.3633=0.5108

f)

probability =P(X>137.9)=P(Z>(137.9-140)/6.085)=P(Z>-0.35)=1-P(Z<-0.35)=1-0.365=0.6350

h)

yes

i)

for 10th percentile critical value of z= -1.28
therefore corresponding value=mean+z*std deviation= 132.2015
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