P( | x | ? x1 | ND: ? = 200, ? = 10) = .40
What is x1?
2.5 |
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5.2 |
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6.5 |
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8.4 |
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12.8 |
Given P( | x | ? x1 | ND: ? = 200, ? = 10) = .40
1 - P( | x | ? x1 | ND: ? = 200, ? = 10) = 1 -0.40
P( | x | < x1 | ND: ? = 200, ? = 10) = 0.60
P(-x1 < X< x1 | ND: ? = 200, ? = 10) 0.60
P( (-x1 -200)/10 < Z < (x1 -200)/10 ) = 0.60
As per standard normal table, P(-0.8416 <Z< 0.8416) = 0.60
Therefore, (x1 -200)/10 = 0.8416
x1 - 200 = 8.416
x1 = 208.416
similiary (-x1 -200)/10 = -0.8416
-x1 - 200 = -8.416
-x1 = 191.584
Correct answer: Option (D) 8.4
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