Question

(1 point) Suppose the number of TV's in a household has a binomial distribution with parameters ?=25 and p=45%.

Find the probability of a household having:

(a) 15 or 22 TV's : 0.0520 (

b) 20 or fewer TV's : 0.999929

(c) 23 or more TV's : 0.10263*10^-5

(d) fewer than 22 TV's : 0.999989

(e) more than 20 TV's :

A-D are all correct

I only need help with E. I got the answer 0.0000226808 and 0.00071 but its telling me its wrong. Is there any other answer im missing? I don't understand why its wrong.

Answer 1

Answer should be 0.000070 not 0.00071. If you watch closely, there are 4 zero's after decimal

Use "binomcdf()" function in TI-84 calculator or use excel formula "=BINOM.DIST.RANGE(25,0.45,0,20)" to find the probability.