Question

A simple random sample of size n =24 is drawn from a population that is normally distributed. The sample mean is found to be x overbar equals 58 and the sample standard deviation is found to be s=12. Construct a 90% confidence interval about the population mean.

The lower bound is?

The upper bound is?

Answer #1

Sample mean =58

Sample standard deviation =12

Sample size =24

Level of significance= 1-0.90=0.1

Degree of freedom =23

t critical value is (by using t table)=
1.714

Confidence interval formula is

=(53.8016,62.1984)

Lower confidence limit= 53.80

Upper confidence limit= 62.20

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