Question

A manufacturer of kitchen utensils wishes to estimate the proportion of left handed people in the population. Obtain a sample size that will ensure a margin of error of at most 0.04 for a 99​% confidence interval estimate of the proportion of left handed people in the population.

n=______ ​(Round up to the nearest​ integer.)

Answer 1

Solution :

Given that,

= 0.5 ( assume 0.5)

1 - = 1 - 0.5 = 0.5

margin of error = E =0.04

At 99% confidence level the z is,

= 1 - 99%

= 1 - 0.99 = 0.01

/2 = 0.005

Z/2 = 2.576 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (2.576 / 0.04)2 * 0.5 * 0.5

=1036.84

Sample size = 1037

Solution :