1.You wish to learn the proportion of MBA students that are female within 3%, and with 98% confidence. How large of a sample should you get?
2. Statistics
Solution:
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E = 3% = 0.03
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
Z/2 = Z0.01 = 2.326
Sample size = n = ((Z / 2) / E)2 * * (1 - )
= (2.326 / 0.03)2 * 0.5 * 0.5
=1503
n = sample size = 1503
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