for binomial distribution
Q1) in a dartball play someone has 5 shot if the probability of success 3÷5 what is the probability of he has 4 success?
Q2) if production life has 5% failed and we select 3 product what is the probability of one of these 3 product failed
(a) P (success) = 3/5
no of shots = 5
we need to find probability that he has 4 success. We will use binomial distribution formula for x success out of N trials where = probability of success
P(4) = 0.2592
Q-2
Probability of failed = 5% = 0.05
P(1) = 0.135375
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