A random sample of 22 students has an average score of 81 and a standard deviation of 9. Form a 95% confidence interval for μ.
We have given that,
Sample mean =81
Sample standard deviation =9
Sample size =22
Level of significance=1-0.95=0.05
Degree of freedom =21
t critical value is (by using t table)=
2.08
Get Answers For Free
Most questions answered within 1 hours.