A civil service exam yields scores with a mean of 81 and a standard deviation of 5.5. Using Chebyshev's Theorem what can we say about the percentage of scores that are above 92?
Using Chebychev's theorem,
We know that,
Minimum percentage of data within two Standard deviation is 75%.
Here,
92 is 2 times standard deviation above the mean.
Hence,
Half of the remaining (100-75)%= 25% data will lies above the 92.
i.e.,
Approximately, 12.5% of scores that are above 92.
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