Question

140 students at a college were asked whether they had completed their required English 101 course,...

140 students at a college were asked whether they had completed their required English 101 course, and 91 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course.
Enter your answers as decimals (not percents) accurate to three decimal places.

The Confidence Interval is ( , )

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
140 students at a college were asked whether they had completed their required English 101 course,...
140 students at a college were asked whether they had completed their required English 101 course, and 91 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( , )
138 students at a college were asked whether they had completed their required English 101 course,...
138 students at a college were asked whether they had completed their required English 101 course, and 109 students said "yes". Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is (  ,  )
30 randomly selected college students were asked whether they prefer to watch football or basketball. 8...
30 randomly selected college students were asked whether they prefer to watch football or basketball. 8 students said they prefer to watch basketball, while the remaining 22 said they prefer to watch football. Go to www.lock5stat.com/StatKey/Links to an external site., but click 'CI for Single Proportion' instead of ‘CI for Single Mean, Median, St.Dev.’ Click on the button near the top of the page that says ‘Edit Data.’ Enter the count and sample size giving in this problem. Then, click...
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a...
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a 99% confidence interval for the proportion of college students who have received the vaccine. - Report the interval as a complete sentence in the context of the problem. - Would a 95% confidence interval be narrower or wider? Why? - Is it possible that the true proportion of vaccinate college students is over 50%? Why or why not?
In a recent survey conducted by a professor of UM, 200 students were asked whether or...
In a recent survey conducted by a professor of UM, 200 students were asked whether or not they have a satisfying experience with the e-learning approach adopted by the school in the current semester. Among the 200 students interviewed, 121 said they have a satisfying experience. What is the 99% confidence interval for the proportion of all UM students who have a satisfying experience with the e-learning approach?
Each of the students was asked whether or not they were employed during the previous summer....
Each of the students was asked whether or not they were employed during the previous summer. 472 of the male students and 588 of the female students said that they had worked during the previous summer. Give a 80% confidence interval for the difference between the proportions of male and female students who were employed during the summer . Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval. Round your answer...
Ages of students: A simple random sample of 100 U.S. college students had a mean age...
Ages of students: A simple random sample of 100 U.S. college students had a mean age of 22.68 years. Assume the population standard deviation is σ = 4.74 years. Construct a 99% confidence interval for the mean age of U.S. college students. The answer I posted my instructor says it is wrong. I came up with 21.45 to 23.91 a 99% confidence interval for the mean of the U.S college students She said the z procedures are needed. Thanks.
In a recent survey conducted by a professor of UM, 200 students were asked whether or...
In a recent survey conducted by a professor of UM, 200 students were asked whether or not they have a satisfying experience with the e-learning approach adopted by the school in the current semester. Among the 200 students interviewed, 121 said they have a satisfying experience. What is the 99% confidence interval for the proportion of all UM students who have a satisfying experience with the e-learning approach? Select one: a. 0.516 to 0.694 b. 0.548 to 0.662 c. 0.524...
In a recent survey conducted by a professor of UM, 200 students were asked whether or...
In a recent survey conducted by a professor of UM, 200 students were asked whether or not they have a satisfying experience with the e-learning approach adopted by the school in the current semester. Among the 200 students interviewed, 121 said they have a satisfying experience. What is the 99% confidence interval for the proportion of all UM students who have a satisfying experience with the e-learning approach? Select one: a. 0.524 to 0.686 b. 0.516 to 0.694 c. 0.537...
A random sample of 205 college students was asked if they believed that places could be...
A random sample of 205 college students was asked if they believed that places could be haunted, and 65 responded yes. Estimate the true proportion of college students who believe in the possibility of haunted places with 99% confidence. According to Time magazine, 37% of all Americans believe that places can be haunted.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT