E(X)=3, V(X)=2, E(Y)=5, and V(Y)=1. If Z=3X-5Y, calculate its expected value and variance. Please give in depth work for part b.
a) E(Z)=-16
b)V(Z)=
There are few formulas we need to use here:
Where, is covariance between X and Y. When X and Y are independent events then covariance is 0.
See the formula for variance, irrespective of + or - in the middle we get all terms positive in right side.
Part a) E(Z) = 3E(X) - 5E(Y) = 3*3 - 5*5 = 9 - 25 = -16
Part b)
Here taken covariance as 0 because X and Y are independent events. (If not then we will get answer in covariance form).
Hence, V(Z) = 43.
Please comment if any doubt. Thank you.
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