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In a survey, 18 people were asked how much they spent on their child's last birthday...

In a survey, 18 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $48.8 and standard deviation of $19.5. Construct a confidence interval at a 98% confidence level.

Express your answer in the format of ¯x ± Error.

$ ± $

Math   Statistics-And-Probability   
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Answer #1

The 98% confidence interval for population mean is

degrees of freedom = n-1 =18-1 =17

For 98% confidence ( ) , with df = 17 , two tailed critical value of t is

tc = 2.567 ( from t table)

Thus , 98% confidence interval for population mean is

Therefore 98% confidence interval for mean is

$ 48.80   $ 11.80

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