Question

Considering the following scenario, which method would be most appropriate when calculating the margin of error for the population mean?

An economist wants to estimate the mean number of school children (in thousands) who read above their grade level in a major city in Georgia. He obtains information from 50 school children in the city and finds the mean to be 7.1 with a population standard deviation known to be 4.8. The population is assumed to be skewed to the right.

-Normal z-distribution

-Student's t-distribution

-More advanced statistical techniques

Answer 1

Answer:-

From the above information we have

n= 50 , xbar = 7.1 , population standard deviation ( = 4.8 )

Here population standard deviation is known

Margin of error =( Z critical at respective level of significance ) * standard error .

Standard error = / square root ( n)

Z is considered for normal distribution which is mainly used for large sample size i.e ( n > 30 ) and population is assumed to be right skewed .

Therefore the most appropriate method when calculating Margin of error for the population mean is - Normal z- distribution.

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