A random sample of 18 college men's basketball games during the last season had an average attendance of
5,061with a sample standard deviation of 1,751.
Complete parts a and b below.
a. Construct a 95% confidence interval to estimate the average attendance of a college men's basketball game during the last season.
b. what assumptions need to be made about this population?
a)
df = n - 1 = 18 - 1 = 17
t critical value at 0.05 significance level with 17 df = 2.110
95% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
5061 - 2.110 * 1751 / sqrt( 18) < < 5061 + 2.110 * 1751 / sqrt( 18)
4190.17 < < 5931.83
95% CI is ( 4190.17 , 5931.83 )
b)
We need to assume that population is normally distributed.
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