Question

The marketing research department is studying the acceptance of customers on a new taste of yogurt....

The marketing research department is studying the acceptance of customers on a new taste of yogurt. In a random sample of 200 customers, 120 state that they like the new taste of yogurt. Construct a 99% confidence interval for the population proportion of customers who like the new taste of yogurt. Interpret your results.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

  Your rating is important

Please rate(like),thank you

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A marketing research company hired by Pepsi is interested in estimating the proportion of cola customers...
A marketing research company hired by Pepsi is interested in estimating the proportion of cola customers in Ontario who prefer Pepsi to other brands. A simple random sample of 120 Ontario cola customers was selected and 45% of them reported favoring other brands over Pepsi. What is the upper limit of the large sample 95% confidence interval for the true proportion of cola customers in Ontario who prefer Pepsi to other brands? (Hint – use 6 decimal places for intermediate...
6. A food company is planning to market a new type of frozen yogurt. The company’s...
6. A food company is planning to market a new type of frozen yogurt. The company’s management will market the yogurt only if at least 45% of the people like it. The company’s research department selected a random sample of 400 persons and asked them to taste this yogurt. Of these 400 persons, 112 said they liked it. Testing at the 2.5% significance level, can the management conclude that they should market the yogurt? Use a p-value test.
A marketing research firm estimates the proportion of potential customers preferring a certain brand of lipstick...
A marketing research firm estimates the proportion of potential customers preferring a certain brand of lipstick by selecting a sample of 100 women who come by their booth in a shopping mall on a specified day. Of the 100 sampled, 65 women stated a preference for brand A. a. What is the target population of this study? b. Did the marketing research firm select a simple random sample? c. Assume this is a random sample: How would you estimate the...
A random sample of 200 physicians indicates that 36 of them make at least $400,000 a...
A random sample of 200 physicians indicates that 36 of them make at least $400,000 a year. Construct a 99% confidence interval estimate of the population proportion of physicians who make at least $400,000 a year. Be sure to state your conclusion.
In a survey of 3398 adults, 1487 say they have started paying bills online in the...
In a survey of 3398 adults, 1487 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (___,___). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last...
In a survey of 3125 adults,1415 say they have started paying bills online in the last...
In a survey of 3125 adults,1415 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A. 99% confidence interval for the population proportion is______ (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is...
In a survey of 3, 487 ​adults, 1,424 say they have started paying bills online in...
In a survey of 3, 487 ​adults, 1,424 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is (_,_). ​(Round to three decimal places as​ needed.) Interpret your results. Choose the correct answer below. A. With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the...
The prices of a random sample of 24 new motorcycles have a sample standard deviation of...
The prices of a random sample of 24 new motorcycles have a sample standard deviation of $3738. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squaredσ2 and the population standard deviation sigmaσ. Use a 99% level of confidence. Interpret the results.
Suppose a marketing company wants to determine the current proportion of customers who click on ads...
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.4 based on a random sample of 90 customers. Compute a 92% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately.
In a survey of 2674 adults, 1470 say they have started paying bills online in the...
In a survey of 2674 adults, 1470 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. 1) The​ 90% confidence interval for the population proportion p is (_,_) (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With​ 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT