An increased number of colleges have been using online resources to research applicants. According to a study from last year, 31% of admissions officers indicated that they visited an applying student's social networking page. A random sample of 200 admissions officers was recently selected and it was found that 65 of them visit the social networking sites of students applying to their college. Using α = 0.01, complete parts a and b below.
a. Does this sample provide support for the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year?
Determine the null and alternative hypotheses.
Choose the correct answer below.
A. H0:p ≤ 0.31
H1:p >0.31
B.H0: p= 0.31
H1:p ≠ 0.31
C. H0: p > 0.31
H1: p ≤ 0.31
D.H0≥ 0.31 0
H1: p l < 0.31
Determine the critical value(s) of the test statistic.
zα= (Use a comma to separate answers as needed. Round to two two decimal places as needed.)
Calculate the test statistic.
zp = (Round to two decimal places as needed.)
Determine the conclusion. Choose the correct answer below.
A. Reject Reject Upper H 0 H0. There is not is not sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year
B. Reject Reject Upper H 0 H0. There is is sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year
C. Do not reject Do not reject Upper H 0 H0. There is not is not sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year
D. Do not reject Do not reject Upper H 0 H0. There is is sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year
b. Determine the p-value for this test.
p-value equals =
(Round to three decimal places as needed.)
Below are the null and alternative Hypothesis,
Null Hypothesis, H0: p <= 0.31
Alternative Hypothesis, Ha: p > 0.31
Rejection Region
This is right tailed test, for α = 0.01
Critical value of z is 2.33.
Hence reject H0 if z > 2.33
Test statistic,
z = (pcap - p)/sqrt(p*(1-p)/n)
z = (0.325 - 0.31)/sqrt(0.31*(1-0.31)/200)
z = 0.46
C. Do not reject Do not reject Upper H 0 H0. There is not is not sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year
b)
P-value Approach
P-value = 0.323
As P-value >= 0.01, fail to reject null hypothesis.
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