Question

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below.

Reyna got a score of 9191; this version has a mean of 72.372.3 and a standard deviation of 1111.

Pierce got a score of 292.2292.2; this version has a mean of 282282 and a standard deviation of 1717.

Frankie got a score of 8.248.24; this version has a mean of 7.27.2 and a standard deviation of 0.80.8.

If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?

Answer 1

The scores of potential candidates could be normalized using Z Score scales. ( whichever candidate has a higher score performed better)

Z -score = ( X - u ) /s

X = score of the candidate, u = mean , s= standard deviation

Reyna

X = 9191 ,u = 72.372.3 and s= 1111

Z - score = ( 9191 - 72.372.3)/1111

Pierce

X= 292.2292.2; u = 282282 and s= 1717

Z - score = ( 292.2292.2 - 282282)/1717

Frankie

X= 8.248.24; u = 7.27.2 and s= 0.80.8

Z - score = ( 8.248.24 - 7.27.2)/0.80.8

Which of the three has the highest z score should be selected.

NOTE : PLEASE CHECK THE VALUES YOU HAVE PROVIDED, THEY HAVE MULTIPLE DECIMALS AND THEY LOOK FISHY. ONCE YOU SUBSTITUTE THE CORRECT NUMBERS IN Z SCORE, YOU WILL ONLY HAVE TO REPORT THE ONE WITH HIGHEST Z-SCORE VALUE.