Try to find out how much time children spend on watching TV. How large should your sample be to be 90% confident that the population mean is within 15 minutes of the sample mean? Assume population standard deviation is 57 minutes. Show all of your calculations.
Solution :
Given that,
Population standard deviation = = 57
Margin of error = E = 15
At 90% confidence level the z is,
= 1 - 90%
= 1 - 0.90 = 0.10
/2 = 0.05
Z/2 = Z0.05 = 1.645
sample size = n = [Z/2* / E] 2
n = [ 1.645 * 57 / 15]2
n = 39.07
Sample size = n = 40
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