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The variance in a production process is an important measure of the quality of the process. A large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance.
2.95 | 3.45 | 3.50 | 3.75 | 3.48 | 3.26 | 3.33 | 3.20 |
3.16 | 3.20 | 3.22 | 3.38 | 3.90 | 3.36 | 3.25 | 3.28 |
3.20 | 3.22 | 2.98 | 3.45 | 3.70 | 3.34 | 3.18 | 3.35 |
3.12 |
3.22 | 3.30 | 3.34 | 3.28 | 3.29 | 3.25 | 3.30 | 3.27 |
3.37 | 3.34 | 3.35 | 3.19 | 3.35 | 3.05 | 3.36 | 3.28 |
3.30 |
3.28 | 3.30 | 3.20 | 3.16 | 3.33 |
1.Find the value of the test statistic. (Round your answer to two decimal places.)
2.Find the p-value. (Round your answer to four decimal places.)
p-value =
Sample 1:
Sample Variance, s₁² = 0.0489
Sample size, n₁ = 25
Sample 2:
Sample variance, s₂² = 0.0058
Sample size, n₂ = 22
α = 0.05
1)
Null and alternative hypothesis:
Hₒ : σ₁² = σ₂²
H₁ : σ₁² ≠ σ₂²
Test statistic:
F = s₁² / s₂² = 0.048889 / 0.0058 =
8.42
2)
Degree of freedom:
df₁ = n₁-1 = 24
df₂ = n₂-1 = 21
P-value :
P-value = 2*F.DIST.RT(8.4163, 24, 21) =
0.0000
Conclusion:
As p-value < α, we reject the null
hypothesis.
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