Question

**Chi-Square Test for Independence**

Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05

Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data).

Response |
Male |
Female |
Total |

Not at all |
23 |
25 |
48 |

Somewhat |
13 |
22 |
35 |

Very |
26 |
16 |
42 |

Total |
62 |
63 |
125 |

What is your null hypothesis?

What is your alternative hypothesis?

What is the Chi-Square value?

Is there significance evidence that a difference exists between the actual males and female responses in this sample and the expected male/female responses in the population? YES OR NO

Answer #1

Chi-Square Test of Independence. A market analyst for an
automobile company suspects there are differences in the vehicle
color preferred by male and female buyers. Advertisements targeted
to the different groups should take such preferences into account
if they exist. The first dataset shows the "observed frequencies"
of the most recent sales. This is followed by partially completed
tables of expected cell frequencies and chi-square calculations.
Please calculate the p-value.
Gender of Buyer
Color
Male
Female
Silver
470
280
Black...

Problem Set 5.4: Alternative to Chi-Square as a Test of
Independence
Criterion: Identify an alternative to
chi-square as a test of independence.
Data: A chi-square test of independence could
be used to examine the relationship between overhead light
preference (on or off) and glasses use (wearing or not
wearing).
Instruction: Answer this: What other type of
test could be used to measure this data? Explain. (hint: the answer
is NOT fishers exact test)

Part 2: Chi-Square Assignment:
The following data are responses to the question
“Does exercising regularly (three or more days per week) until
you sweat and breathe hard appeal to you?” Response levels to the
question are “very much,” “somewhat,” or “not at all.”
A total of 90 boys and 80 girls responded to the question.
(These are not real data. The responses are made up to demonstrate
chi square. It is hoped and believed that boys and girls think that...

Chapter 18
Chi-square – Test of Independence
Certain editors at Sage like to think they’re a bit of a
whiz at soccer. To see how well they play compared with Sussex
lecturers and postgraduates, we invited various employees of Sage
to join in our soccer matches. Every player was allowed only to
play in one match. Over many matches, we counted the number of
players that scored goals. After running a chi-square test of
independence, determine whether or not the...

Use the Chi-square test for independence to test the null
hypothesis of no association between cigarette smoking and asthma
symptoms. The expected cell counts, have been computed for you.
Ever Smoked Cigarettes (OBSERVED)
Symptoms of Asthma
Yes
No
Total
Yes
20
30
50
No
22
78
100
Total
42
108
150
Ever Smoked Cigarettes (EXPECTED)
Symptoms of Asthma
Yes
No
Total
Yes
14
36
50
No
28
72
100
Total
42
108
150
4) (10 points) Conduct the test at...

1.) Why is it not possible to calculate a chi-square on the
following hypothesis: Males have a higher number of
total arrests than females?
2.) What statistical test would a researcher use to test the
following research hypothesis: Individuals who
report less favorable attitudes toward the police (measured as 1 =
very favorable, 2 = somewhat favorable, 3 = somewhat not favorable,
and 4 = not at all favorable) are more likely to be sentenced to
higher security prisons (measured as 1...

by utilizing this chi-Square Test answer the following question
and explain what the table means.
Are Americans in favor of the use of unmanned drones by
police agencies in the United States?
Table 4
Chi-Square Test for Association: Gender, Opinion
Gender
-1
0
1
Total
39
17
44
100
Male
39.2
25.13
35.68
0.0010
2.6278
1.9409
39
33
27
99
Female
38.8
24.87
35.32
0.0010
2.6544
1.9605
Total
78
50
71
199
Note. Possible responses (-1, 0, and 1). -1...

PLEASE ANSWER ALL QUESTIONS !
1.
When performing a Chi-Square test, what is the critical value
between the accept and reject regions for a test with 5 classes and
25 observations at the 5% level of significance?
Select one:
a. 11.070
b. 2.87
c. 2.60
d. 9.488
2. True or False: A hypothesis is a statement about a population
developed for the purpose of testing.
Select one:
True
False
3. If you ACCEPT the null hypothesis while performing a
Chi-Square...

QUESTION 24
A study examines fitness differences between males and females.
A chi-square test of association is used to test the results. The
results are displayed in the following table:
Gender
Fit
Not Fit
Total
X2,df
p
Male n (%)
24 (41.8%)
34 (58.6%)
58
5.76, 1
.02
Female n (%)
34 (64.2%)
19 (35.8%)
53
Total
58
53
111
The most appropriate interpretation of these results is:
1.
Fitness levels were similar in men and women. There is no
siginficant...

CONTINUED ON NEXT PAGE
Problem Set 2: Chi Square Test for
Independence
Research Scenario: A psychology student at a
university is curious whether students in different majors (IV)
have different class time preferences (DV), or whether class time
preference is independent of major. After doing some preliminary
research, she chooses three different majors and recruits 10
volunteers from each major. She then asks them to choose their
preferred class time—either morning or afternoon. The results are
listed in the table...

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